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Box has 5 red, 7 blue balls. Draw 2 without replacement. P(both red):
A(5/12)(4/11) = 20/132 = 5/33
B0
C1/2
D5/12 × 5/12
Answer & Solution
Correct answer: A. (5/12)(4/11) = 20/132 = 5/33
First red: 5/12. Second red (one less red, one less total): 4/11. Joint: (5/12)(4/11) = 20/132 = 5/33.
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