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Self-crossing an F1 heterozygote is drawn using a Punnett square of size:
A3 by 3
B4 by 4
C5 by 5
D2 by 2
Answer & Solution
Correct answer: D. 2 by 2
1. Each parent can donate one of two different alleles.
2. That gives two rows and two columns.
3. So the square is 2 by 2.
_Source: OpenStax Biology 2e, Chapter 12, Mendel's Experiments and Heredity._
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