A conductor carries a steady current of $3\,\text{A}$ for $20\,\text{s}$. How much charge passes through it?
A$\,\,\,\,0.15\,\text{C}$
B$17\,\text{C}$
C$23\,\text{C}$
D$60\,\text{C}$
Answer & Solution
Correct answer: D. $60\,\text{C}$
Using $I=\dfrac{Q}{t}$, we get $Q=It=3\times 20=60\,\text{C}$. Hence the amount of charge passing is $60\,\text{C}$.
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