Integral ∫ 1/(1 + x²) dx =
A1/x
Barcsin(x)
Carctan(x) + C
Dln(1+x²)
Answer & Solution
Correct answer: C. arctan(x) + C
∫ dx/(1+x²) = arctan(x) + C. Standard integral. Application in inverse trig substitution.
Related questions
The value of $ in(\tan^{-1}(3/4))$ is:The value of $\cos^{-1}(-1)$ is:For $x \in [-1, 1]$, the identity $ in^{-1}x + \cos^{-1}x$ equals:The principal value of $ in^{-1}(1/2)$ is:Maximum value of x² + (arcsin(x))² for x in [-1, 1]:arctan(x) is an _____ function (odd/even):Range of f(x) = arcsin(x) - arccos(x):Integral ∫ 1/sqrt(1 - x²) dx =