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Range of f(x) = arcsin(x) + arccos(x):
AEmpty
B[0, π]
C{π/2} (constant function, equals π/2 always on [-1, 1])
D[-π/2, π/2]
Answer & Solution
Correct answer: C. {π/2} (constant function, equals π/2 always on [-1, 1])
For all x ∈ [-1, 1]: arcsin(x) + arccos(x) = π/2 (constant identity). Hence range is single point {π/2}.
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