If the distance between two point charges is doubled while the charges remain unchanged, the electrostatic force becomes
Afour times
Btwo times
Chalf
Done-fourth
Answer & Solution
Correct answer: D. one-fourth
From Coulomb's law, $F \propto \frac{1}{r^2}$. If $r$ becomes $2r$, then the new force is $F' = \frac{F}{2^2} = \frac{F}{4}$. So the force becomes one-fourth.
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