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Two point charges are separated by a distance $r$. If one charge is doubled and the other remains unchanged, the new electrostatic force is
A$F/2$
B$F$
C$2F$
D$4F$
Answer & Solution
Correct answer: C. $2F$
Since $F = k\dfrac{q_1 q_2}{r^2}$, doubling one charge doubles the product $q_1 q_2$. With distance unchanged, the force also doubles, so the new force is $2F$.
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