Two point charges are separated by a distance $r$. If one charge is doubled and the other remains unchanged, the new electrostatic force is
A$F/2$
B$F$
C$2F$
D$4F$
Answer & Solution
Correct answer: C. $2F$
Since $F = k\dfrac{q_1 q_2}{r^2}$, doubling one charge doubles the product $q_1 q_2$. With distance unchanged, the force also doubles, so the new force is $2F$.
Related questions
If a positive point charge is placed at the centre of a spherical conducting shell of radiThe SI unit of electric field isFor a charge distribution with volume density ρ, the total charge Q equalsThe electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻Two charges +q and −q of equal magnitude are placed at the corners A and B of an equilaterThe principle of quantisation of electric charge is stated asAn electric dipole in a uniform electric field E experiencesThe electric field on the axial line of a short electric dipole at distance r is