alleryIf $q_1 = q_2 = 1\,\text{C}$ and $r = 1\,\text{m}$ in the relation $F = k\dfrac{q_1 q_2}{r^2}$, then the magnitude of the force is
A$1/k$
B$k$
C$k^2$
D$0$
Answer & Solution
Correct answer: B. $k$
Substituting $q_1 = 1\,\text{C}$, $q_2 = 1\,\text{C}$, and $r = 1\,\text{m}$ gives $F = k\dfrac{1\cdot1}{1^2} = k$.
**So the force magnitude equals $k$.**
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