If $q_1 = q_2 = 1\, ext{C}$ and $r = 1\, ext{m}$ in the relation $F …

Question

If $q_1 = q_2 = 1\,	ext{C}$ and $r = 1\,	ext{m}$ in the relation $F = k\dfrac{q_1 q_2}{r^2}$, then the magnitude of the force is

Accepted Answer

B. $k$

Substituting $q_1 = 1\,	ext{C}$, $q_2 = 1\,	ext{C}$, and $r = 1\,	ext{m}$ gives $F = k\dfrac{1\cdot1}{1^2} = k$. So the force magnitude equals $k$.

Answer

$1/k$

Answer

$k^2$

Answer

$0$

If $q_1 = q_2 = 1\,\text{C}$ and $r = 1\,\text{m}$ in the relation $F = k\dfrac{q_1 q_2}{r^2}$, then the magnitude of the force is