alleryIf both charges are doubled and the separation between them is kept unchanged, the electrostatic force becomes
Aunchanged
Bdoubled
Cfour times
Deight times
Answer & Solution
Correct answer: C. four times
The force is $F = k\dfrac{q_1 q_2}{r^2}$.
Doubling both charges changes the product from $q_1 q_2$ to $(2q_1)(2q_2)=4q_1q_2$, so the force becomes four times the original value.
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