alleryHalf-life of radioactive sample is T₁/₂. Decay constant λ:
Aλ = 2 T₁/₂
Bλ = T₁/₂
Cλ = ln 2 / T₁/₂ ≈ 0.693/T₁/₂
Dλ = 1/T₁/₂
Answer & Solution
Correct answer: C. λ = ln 2 / T₁/₂ ≈ 0.693/T₁/₂
N(t) = N₀ e^(-λt).
After T₁/₂, N = N₀/2
We have → e^(-λ T₁/₂) = 1/2 → λ T₁/₂.
That is → e^(-λ T₁/₂) = ln 2 → λ.
So → e^(-λ T₁/₂) = 0.693/T₁/₂.
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