alleryDistance between two parallel planes 2x + y + z = 5 and 2x + y + z = 10:
A5
Bsqrt(6)
C1
D5/sqrt(6) (= |d₁ - d₂|/sqrt(a²+b²+c²))
Answer & Solution
Correct answer: D. 5/sqrt(6) (= |d₁ - d₂|/sqrt(a²+b²+c²))
Parallel planes have same normal (a, b, c).
Distance = |d₂ - d₁|/sqrt(a²+b²+c²) = |10-5|/sqrt(4+1+1) = 5/sqrt(6).
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