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For a full-wave bridge rectifier with AC input V_rms, peak DC output voltage:

AV_rms
BV_peak × 0.5
CV_rms/2
DV_rms × sqrt(2) (= V_peak), minus 2 × diode drop
Answer & Solution
Correct answer: D. V_rms × sqrt(2) (= V_peak), minus 2 × diode drop
Peak input voltage = V_rms × sqrt(2). For bridge rectifier, output passes through 2 diodes each half-cycle: V_peak_out = V_rms × sqrt(2) - 2 × 0.7 V (Si). With capacitor filter, output approaches V_peak.
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