Solve dy/dx + y = sin x:
Ay = -x
By = sin x
Cy = cos x
Dy = (sin x - cos x)/2 + C e^(-x)
Answer & Solution
Correct answer: D. y = (sin x - cos x)/2 + C e^(-x)
Linear, P = 1, μ = e^x. (e^x y)' = e^x sin x.
∫e^x sin x dx = (e^x/2)(sin x - cos x).
So e^x y = (e^x/2)(sin x - cos x) + C
→ y = (sin x - cos x)/2 + C e^(-x).
Keep practising Unit 7: Differential Equations and Modeling
Browse all Unit 7: Differential Equations and Modeling questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
Mode of {1, 2, 2, 3, 4, 4, 4, 5}:A matrix with all elements zero is called:arccos(x) + arccos(-x) =Simplify arctan(sin x / (1+cos x)) for x ∈ (-π, π):Value of arctan(1):Number of rows in matrix A times number of columns in A x B should equal:The half-life of a radioactive substance decaying by $dm/dt = -km$ (with $k > 0$) in termsSolve $\dfrac{dy}{dx} = \dfrac{y + qrt{x^2 + y^2}}{x}$.