alleryOrder and degree of (d²y/dx²)² + y = 0:
A1 and 2
B2 and 2 (2nd-order, squared)
CNot defined
D2 and 1
Answer & Solution
Correct answer: B. 2 and 2 (2nd-order, squared)
Highest order derivative is d²y/dx² (order = 2).
It's raised to power 2 (degree = 2).
Both well-defined here since no radicals/fractions of derivatives.
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