alleryIntegrating factor for dy/dx + y = e^x:
Aln x
Be^x (∫1 dx = x; e^x as IF)
Cx
D1
Answer & Solution
Correct answer: B. e^x (∫1 dx = x; e^x as IF)
P(x) = 1. μ = e^(∫1 dx) = e^x.
Then (e^x y)' = e^x × e^x = e^(2x).
**Integrate:** e^x y = e^(2x)/2 + C → y = e^x/2 + C e^(-x).
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