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Two volatile liquids A (P°_A = 100) and B (P°_B = 200) form ideal solution. For x_A = 0.4, total vapor pressure:
A150
B100
C160 (= 100 × 0.4 + 200 × 0.6)
D300
Answer & Solution
Correct answer: C. 160 (= 100 × 0.4 + 200 × 0.6)
P_total = P°_A x_A + P°_B x_B = 100 × 0.4 + 200 × 0.6 = 40 + 120 = 160 mmHg. (Linear in composition for ideal mixtures.)
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