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Mole fraction of solute x_B in a binary solution:
A1 - n_A
Bn_B / (n_A + n_B)
Cn_B / n_A
Dn_A / n_B
Answer & Solution
Correct answer: B. n_B / (n_A + n_B)
x_B = n_B / (n_A + n_B) where n_A is moles of solvent, n_B is moles of solute. x_A + x_B = 1. Dimensionless. Used in Raoult's law, Henry's law.
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