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Integration by substitution: ∫ 2x × e^(x²) dx = (let u = x²)
Ae^(x²) + C
Be^x + C
C2 e^(x²)
Dx²/2
Answer & Solution
Correct answer: A. e^(x²) + C
Let u = x², du = 2x dx. So integral becomes ∫ e^u du = e^u + C = e^(x²) + C.
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