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The Pythagorean triplet with 8 as its smallest member is:

A8, 10, 12
B8, 12, 16
C8, 9, 10
D8, 15, 17
Answer & Solution
Correct answer: D. 8, 15, 17
1. Take 2m = 8, so m = 4. 2. Then m squared minus 1 is 15 and m squared plus 1 is 17. 3. The triplet is 8, 15, 17. _Source: syllabus Mathematics, Chapter 6, Squares and Square Roots._
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