Home › SSC CGL › Quantitative Aptitude › Square Roots › The sum of the first 6 odd numbers, 1+3+5+7+9+11…
The sum of the first 6 odd numbers, 1+3+5+7+9+11, equals:
A42
B36
C21
D30
Answer & Solution
Correct answer: B. 36
1. The sum of the first n odd numbers is n squared.
2. Here n is 6.
3. 6 squared is 36.
_Source: NCERT Class 8 Mathematics, Chapter 6, Squares and Square Roots._
Related questions
A right triangle has hypotenuse 5 cm and one side 3 cm. The third side squared is:90 = 2 x 3 x 3 x 5. Since 2 and 5 are unpaired, 90 is:The square root of 6400 is:48 = 2x2x2x2x3 has one unpaired 3. The smallest number to multiply 48 by to get a perfect 256 = 2x2x2x2x2x2x2x2. Pairing the factors, its square root is:Subtracting 1, 3, 5, ... from 81 reaches 0 at the 9th step. So the square root of 81 is:A perfect square has two integral square roots; the root symbol denotes only the:Finding a number whose square is known is called finding the: