For second-order reaction (single reactant), integrated rate law:
A1/[A] - 1/[A]₀ = kt
Bln[A] vs t straight
C[A]₀ - [A] = kt
DSame as first
Answer & Solution
Correct answer: A. 1/[A] - 1/[A]₀ = kt
d[A]/dt = -k[A]² integrates to 1/[A] = 1/[A]₀ + kt. Plot 1/[A] vs t is straight line. Half-life t₁/₂ = 1/(k[A]₀) depends on initial concentration.
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