The surface area of a cuboid with edges l, b and h is:
A2(lb + bh + hl)
Blb + bh + hl
C4(lb + bh + hl)
D3(lb + bh + hl)
Answer & Solution
Correct answer: A. 2(lb + bh + hl)
1. Opposite faces of a cuboid are equal in area.
2. So each of the three distinct face areas appears twice.
3. The total is 2 times lb plus bh plus hl.
_Source: NCERT Class 9 Mathematics, Chapter 13, Surface Areas and Volumes._
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