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Quadratics were earlier solved over the reals when the discriminant was:

AImaginary
BNon-negative
CStrictly zero
DIrrational
Answer & Solution
Correct answer: B. Non-negative
1. Real solutions need a real square root of the discriminant. 2. That exists only when the discriminant is not below zero. 3. So the earlier cases had a non-negative discriminant. _Source: syllabus Mathematics, Chapter 5, Complex Numbers and Quadratic Equations._
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