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A compound of nitrogen and hydrogen is 87.4% nitrogen by mass. Its empirical formula is:

ANH
BNH2
CNH3
DN2H
Answer & Solution
Correct answer: B. NH2
1. Take 100 g: 87.4 g nitrogen and $100-87.4=12.6$ g hydrogen. 2. Divide by relative atomic masses: nitrogen $\dfrac{87.4}{14}=6.243$, hydrogen $\dfrac{12.6}{1}=12.6$. 3. Divide both by the smaller: nitrogen $1$, hydrogen $\dfrac{12.6}{6.243}=2.02$. 4. The simplest whole-number ratio is therefore $1:2$. 5. The empirical formula is NH₂. Forgetting to subtract from 100 to get the hydrogen percentage is the usual first slip. _Source: NECTA ACSEE 2023 Chemistry 132/1, Question 1: Gases_
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