A current-carrying wire of length L in magnetic field B experiences force:
ABIL
BBIL sin theta
CB²IL
DBI/L
Answer & Solution
Correct answer: B. BIL sin theta
F = IL × B (vector form).
Magnitude F = BIL sin theta where theta is angle between current direction and B. Maximum when perpendicular (theta = 90 degrees).
Keep practising Electromagnetism
Browse all Electromagnetism questions for JEE Advanced, or explore more Physics topics.
Related questions
For a charge distribution with volume density ρ, the total charge Q equalsThe electric flux through a closed surface enclosing a charge of +5 μC is (ε₀ = 8.85 × 10⁻The electric field on the axial line of a short electric dipole at distance r isAn electric dipole consists of two equal and opposite point charges ±q separated by distanGauss's law states that the total electric flux through a closed surface equalsThe electric field just outside a uniformly charged infinite plane with surface charge denThe electric field of an infinite line of charge with linear charge density λ at perpendicThe electric field at distance r from an isolated point charge q is