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Out of 14 ads in a break, how many did not have children in them?

AThree
BFour
CSeven
DEight
Answer & Solution
Correct answer: B. Four
1. There were 14 ads in each break. 2. Children appeared in 10 of them. 3. So 14 minus 10, which is 4, had no children. _Source: syllabus Mathematics, 'Math-Magic', Ch 12 'Smart Charts'_
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