Examine the nature of the roots of $x^2+8x+16=0$.

Question

Accepted Answer

B. Real and equal

For $x^2+8x+16=0$, the discriminant is $D=b^2-4ac=8^2-4\cdot1\cdot16=64-64=0$.
When the discriminant is zero, the quadratic has real and equal roots.
In fact, the equation factors as $(x+4)^2=0$.

Answer

Real and distinct

Answer

Imaginary and conjugate

Answer

Real, irrational and distinct

Examine the nature of the roots of $x^2+8x+16=0$.

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