For the cell: Zn|Zn²⁺(0.1 M)||Cu²⁺(0.01 M)|Cu, at 25°C, E_cell is:
A1.07 V
B1.13 V
C1.04 V
D1.10 V
Answer & Solution
Correct answer: A. 1.07 V
Nernst: E = E° - (0.0591/2) log([Zn²⁺]/[Cu²⁺]) = 1.10 - 0.02955 × log(0.1/0.01) = 1.10 - 0.02955 × 1 = 1.07 V (approximately).
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