For SHM x = A sin(ωt), find ratio of kinetic energy at t = T/4 to t = T/8:
A1:2
BCannot determine
C0:1
D2:1
Answer & Solution
Correct answer: C. 0:1
At t = T/4: ωt = π/2, x = A, v = 0 → KE = 0. At t = T/8: ωt = π/4, v = Aω cos(π/4) = Aω/√2 → KE = (1/2)mA²ω²/2 > 0. So ratio is 0 : positive = 0:1.
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