alleryA particle executing SHM has time period T. Time taken to go from extreme to mid-amplitude position:
AT/8
BT/6
CT/12
DT/4
Answer & Solution
Correct answer: C. T/12
From x = A cos(ωt) at extreme: at x = A/2, A cos(ωt) = A/2, so cos(ωt) = 1/2, ωt = π/3. Time t = T/6 from extreme to A/2... wait.
**Let me redo:** extreme to mid-amplitude (A to A/2). x = A cos(ωt).
We have x = A/2 → cos(ωt).
So x = 1/2.
→ ωt = π/3 → t = T/(2π) × π/3 = T/6. So T/6. Let me re-check options.
**The answer should be T/6, option B. Setting B.**
Keep practising Unit 1C: Kinematics: Relative & Circular Motion
Browse all Unit 1C: Kinematics: Relative & Circular Motion questions for AP Physics 1, or explore more Physics topics.
Related questions
A solid sphere of mass M, radius R rolls without slipping down an incline of angle theta. For a hoop, disc, and solid sphere of same mass and radius rolling down an incline. Order A figure skater pulls in her arms during a spin. Her moment of inertia decreases. By conseTwo point masses 3 kg each at the ends of a massless rod of length 4 m. I about axis throuA solid cylinder and a hollow cylinder of same mass and radius roll down an incline. WhichFor a body rolling without slipping with velocity v of center of mass:Kinetic energy of a rotating body with moment of inertia I and angular velocity omega:For a thin rod of mass M and length L, I about axis through center perpendicular to rod: