Aniline with bromine water at room temperature gives:
A2,4,6-trichloroaniline
B2,4,6-triiodoaniline
C2,4,6-trinitroaniline
D2,4,6-tribromoaniline
Answer & Solution
Correct answer: D. 2,4,6-tribromoaniline
1. The amino group activates the ring strongly.
2. It directs to the two ortho and one para positions.
3. All three are brominated, giving a white precipitate.
_Source: NCERT Class 12 Chemistry Part 2, Unit 9 'Amines'_
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