The nth term of a GP is:
Aa - r(n-1)
Ba / r(n-1)
Ca r^(n-1)
Da + r(n-1)
Answer & Solution
Correct answer: C. a r^(n-1)
1. A GP is a, ar, ar squared and so on.
2. By the nth term, r has multiplied n minus 1 times.
3. So the nth term is a times r to the power n minus 1.
4. The answer is a r^(n-1).
_Source: NCERT Class 9 Mathematics, Ch 8 'Predicting What Comes Next: Exploring Sequences and Progressions'_
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