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The nth term of a GP is:

Aa - r(n-1)
Ba / r(n-1)
Ca r^(n-1)
Da + r(n-1)
Answer & Solution
Correct answer: C. a r^(n-1)
1. A GP is a, ar, ar squared and so on. 2. By the nth term, r has multiplied n minus 1 times. 3. So the nth term is a times r to the power n minus 1. 4. The answer is a r^(n-1). _Source: syllabus Mathematics, Ch 8 'Predicting What Comes Next: Exploring Sequences and Progressions'_
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