The nth term of an AP is:
Aa / (n-1)d
Ba + (n-1)d
Ca - (n-1)d
Da x (n-1)d
Answer & Solution
Correct answer: B. a + (n-1)d
1. An AP is a, a plus d, a plus 2d and so on.
2. By the nth term, d has been added n minus 1 times.
3. So the nth term is a + (n-1)d.
4. The answer is a + (n-1)d.
_Source: syllabus Mathematics, Ch 8 'Predicting What Comes Next: Exploring Sequences and Progressions'_
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