Boiling point elevation: ΔT_b = K_b × m. For 1 molal aqueous urea (K_b = 0.52 K kg/mol), ΔT_b equals:
A0.52 K
B0.26 K
C1.04 K
D0.052 K
Answer & Solution
Correct answer: A. 0.52 K
ΔT_b = K_b × m = 0.52 × 1 = 0.52 K. So 1 m urea raises BP by 0.52 K above pure water's 100°C.
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