In a car race, two-third of B's rate is equal to three-fourth of A's rate. If the distance is 1080 km and the speed of A is given as 120 kmph, how long would B take to finish the race?
A12 hrs
B9 hrs
C10 hrs
D8 hrs
Answer & Solution
Correct answer: D. 8 hrs
Given $\frac{2}{3}B=\frac{3}{4}A$ and $A=120$. So $B=\frac{3}{2}\cdot \frac{3}{4}\cdot 120=135$ km/hr. Time taken by B to cover $1080$ km is $\frac{1080}{135}=8$ hours. Hence option D is correct.
Related questions
Which of the following is a linear equation in one variable?A number divided by 2 is 5 less than the number itself. What is the number?The sum of three consecutive integers is 24. What are the integers?For the pair of linear equations $3x+2y=12$ and $-x+y=3$, what does the graphical solutionUsing the graph of $3x+2y=12$ and $-x+y=3$, what is the solution of the system?
![](httpsSolve the system by elimination: $x+y=7$ and $3x+2y=10$.A system of two linear equations in two variables has infinitely many solutions when whichWhat is the discriminant of the quadratic equation $Ax^2+Bx+C=0$?