∫ cosec² x dx equals:
Acot x + C
Bsec x + C
C-cot x + C
Dtan x + C
Answer & Solution
Correct answer: C. -cot x + C
d/dx (-cot x) = cosec² x. So ∫ cosec² x dx = -cot x + C. (Compare: ∫ sec² x dx = tan x + C.)
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