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∫ ln x dx (by parts):

Ax ln x - x + C
B1/x + C
Cln x + C
Dx ln x + x + C
Answer & Solution
Correct answer: A. x ln x - x + C
Let u = ln x, dv = dx, du = dx/x, v = x. We have ∫ ln x dx = x ln x - ∫ x · (1/x). So dx = x ln x - x + C.
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