alleryA weak base BOH has Kb = 1.8 × 10⁻⁵. pH of 0.1 M solution is approximately:
A9
B11
C3
D8
Answer & Solution
Correct answer: B. 11
[OH-] ≈ √(Kb × C) = √(1.8 × 10⁻⁶) ≈ 1.34 × 10⁻³.
pOH = -log(1.34 × 10⁻³) ≈ 2.87. pH = 14 - 2.87 ≈ 11.13.
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