A batsman strikes a ball of mass $0.15$ kg moving at $20$ m/s, sending it back at $20$ m/s. The impulse on the ball is:
A$3$ Ns in the original direction of the ball
B$3$ Ns in the same direction as the bat swing only
C$6$ Ns opposite to the original direction of the ball
DZero, since the speed magnitude is unchanged by the hit
Answer & Solution
Correct answer: C. $6$ Ns opposite to the original direction of the ball
$\Delta p = 0.15\times 20 - (-0.15\times 20) = 6$ Ns opposite to original motion.
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