A galvanometer of resistance G is converted into a voltmeter reading f…

Question

A galvanometer of resistance G is converted into a voltmeter reading full-scale voltage V by

Accepted Answer

B. {'text': 'A high resistance R = V/I_g − G placed in series', 'label': 'B'}

1. A voltmeter must read a voltage with negligible current draw.
2. A high resistance R is placed in series with the galvanometer.
3. Full-scale voltage V corresponds to full-scale current I_g through (G + R).
4. So V = I_g (G + R), giving R = V / I_g − G.
_Source: NCERT Class 12 Physics, Ch 3 "Current Electricity", §3 measurement_

Answer

{'text': 'Adding a small shunt resistor across the coil', 'label': 'A'}

Answer

{'text': 'Removing the coil resistance from the circuit', 'label': 'C'}

Answer

{'text': 'Placing a capacitor of unit farad in series', 'label': 'D'}