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A normal distribution has a third quartile of 46.3 and a first quartile of 27.5. What is the interquartile range?

AIt is 73.8
BIt is 36.9
CIt is 9.4
DIt is 18.8
Answer & Solution
Correct answer: D. It is 18.8
1. The interquartile range is the third quartile minus the first quartile. 2. That is 46.3 minus 27.5. 3. The subtraction gives 18.8. 4. Answering 73.8 adds the quartiles instead of subtracting them. _Source: OpenStax High School Statistics (CC BY 4.0), Ch 6 "The Normal Distribution", section 6.2 Using the Normal Distribution_
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