Solve 3(x - 2) less than or equal to 5x + 4 and write the answer in interval notation.

1. Distribute the 3 to get 3x minus 6 on the left. 2. Subtract 3x from both sides to get negative 6 less than or equal to 2x plus 4. 3. Subtract 4 from both sides to get negative 10 less than or equal to 2x. 4. Divide both sides by 2, a positive number, so the sign stays as it is. 5. That gives negative 5 less than or equal to x, which reads x is at least negative 5. 6. Since negative 5 itself works, the endpoint is included, giving [-5, infinity). 7. The interval (-infinity, -5] reverses the sign even though no negative divisor was used. 8. The interval [5, infinity) loses the minus sign at the final division step. 9. The interval (-infinity, 5] makes both of those errors at once. _Source: OpenStax Intermediate Algebra (CC BY 4.0), Ch 2 "Solving Linear Equations", section 2.5 Solve Linear Inequalities_