Practice free →
HomeNEET UG › Mechanics › A spring is stretched by 0.1 m; its stiffness is…

A spring is stretched by 0.1 m; its stiffness is 200 N/m. The energy stored is:

A0.5 J
B1 J
C2 J
D4 J
Answer & Solution
Correct answer: B. 1 J
U = ½·200·(0.1)² = ½·200·0.01 = 1 J.
Solve this in the app — NEET UG practice & 24k+ MCQs →
Related questions