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In Fig. 6.29, if $PQ \parallel RS$, which pair of triangles is similar? 
A$\triangle POQ \sim \triangle ROS$
B$\triangle POQ \sim \triangle SOR$
C$\triangle POQ \sim \triangle RSO$
D$\triangle PQO \sim \triangle OSR$
Answer & Solution
Correct answer: B. $\triangle POQ \sim \triangle SOR$
Because $PQ \parallel RS$, we get $\angle P = \angle S$ and $\angle Q = \angle R$ as alternate interior angles. Also, $\angle POQ = \angle SOR$ as vertically opposite angles. Therefore, by AAA similarity, $\triangle POQ \sim \triangle SOR$. The order matters: $P \leftrightarrow S$, $O \leftrightarrow O$, and $Q \leftrightarrow R$.
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