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What volume of a 1.00 M Fe(NO3)3 stock can be diluted to prepare 1.00 L of a 0.250 M solution?
A0.250 L
B4.00 L
C0.750 L
D1.25 L
Answer & Solution
Correct answer: A. 0.250 L
1. Use the dilution equation C1V1 = C2V2.
2. Solve for V1: V1 = 0.250 M x 1.00 L / 1.00 M.
3. That gives 0.250 L of the stock solution.
4. The value 0.750 L is the water added rather than the stock measured out.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_
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