Layla jogs with an average velocity of 2.4 m/s east. Using displacement = average velocity x time, what is her displacement after 46 seconds?

1. Rearrange the average velocity formula v = d/t to solve for displacement: d = v x t. 2. Substitute the given values: d = 2.4 m/s x 46 s = 110.4 m. 3. The worked example states this result directly: "about 110 m east." 4. 19 m comes from mistakenly dividing 46 by 2.4 instead of multiplying; 46 m and 2.4 m east simply repeat the given time and velocity values without combining them. 5. So Layla's displacement after 46 s is about 110 m east. _Source: OpenStax Physics Ch 2 "Motion in One Dimension", p.68 Worked Example §2.2 Speed and Velocity_