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Layla jogs with an average velocity of 2.4 m/s east. Using displacement = average velocity x time, what is her displacement after 46 seconds?
A19 m east
B46 m east
C2.4 m east
DAbout 110 m east
Answer & Solution
Correct answer: D. About 110 m east
1. Rearrange the average velocity formula v = d/t to solve for displacement: d = v x t.
2. Substitute the given values: d = 2.4 m/s x 46 s = 110.4 m.
3. The worked example states this result directly: "about 110 m east."
4. 19 m comes from mistakenly dividing 46 by 2.4 instead of multiplying; 46 m and 2.4 m east simply repeat the given time and velocity values without combining them.
5. So Layla's displacement after 46 s is about 110 m east.
_Source: OpenStax Physics Ch 2 "Motion in One Dimension", p.68 Worked Example §2.2 Speed and Velocity_
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