To find a jet car's instantaneous velocity at t = 25 s, the tangent line to its position-time graph at that point passes through (19 s, 1300 m) and (32 s, 3120 m). What is the instantaneous velocity at t = 25 s?

1. Instantaneous velocity at a point equals the slope of the line tangent to the curve at that point. 2. The two endpoints given for the tangent line are (19 s, 1300 m) and (32 s, 3120 m). 3. Slope = (3120 m − 1300 m) / (32 s − 19 s) = 1820 m / 13 s = 140 m/s. 4. The other options come from arithmetic slips such as using the wrong endpoint pair or misplacing a digit -- always recompute rise/run directly from the two stated points. 5. So the instantaneous velocity of the jet car at t = 25 s is 140 m/s. _Source: OpenStax Physics Ch 2 "Motion in One Dimension", p.74 Worked Example §2.3 Position vs. Time Graphs_