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On the jet car's velocity-time graph, a rectangular region (20 m/s over 30 s) contributes 600 m and a triangular region (base 30 s, height 140 m/s) contributes 2,100 m. What is the net displacement over the interval?
A1,500 m
B2,700 m
C2,100 m
D4,200 m
Answer & Solution
Correct answer: B. 2,700 m
1. The total area under a velocity-time graph equals the total displacement, and complex shapes can be split into simpler ones.
2. Add the rectangle's contribution and the triangle's contribution: 600 m + 2,100 m.
3. "Add them together to get a net displacement of 2,700 m," as the worked example states.
4. 1,500 m and 4,200 m come from adding or combining the pieces incorrectly; 2,100 m is only the triangle's contribution, ignoring the rectangle.
5. So the net displacement over the whole interval is 2,700 m.
_Source: OpenStax Physics Ch 2 "Motion in One Dimension", p.78 Worked Example §2.4 Velocity vs. Time Graphs_
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