On a jet-powered car's position-time graph, two points are (0.50 s, 525 m) and (6.4 s, 2000 m). What is the car's average velocity between these points?

1. Average velocity is the slope between the two points: (change in position) / (change in time). 2. Change in position = 2000 m − 525 m = 1475 m. Change in time = 6.4 s − 0.50 s = 5.9 s. 3. Average velocity = 1475 m / 5.9 s = 250 m/s. 4. This matches the text's own cross-check in km/h: "an impressively high land speed (900 km/h..." and 250 m/s x 3.6 = 900 km/h exactly. 5. So the car's average velocity between these two points is 250 m/s. _Source: OpenStax Physics Ch 2 "Motion in One Dimension", p.73 Worked Example §2.3 Position vs. Time Graphs_