Home › NPCIL Trainee › Physics › Motion in One Dimension › A car drives 5 km from home to school, then driv…
A car drives 5 km from home to school, then drives 5 km back home along the same road. What are the total distance travelled and the net displacement for the round trip?
ADistance 0 km, displacement 10 km
BDistance 5 km, displacement 5 km
CDistance 10 km, displacement 0 km
DDistance 10 km, displacement 10 km
Answer & Solution
Correct answer: C. Distance 10 km, displacement 0 km
1. Distance is the total length of the path travelled, regardless of direction: 5 km out + 5 km back = 10 km.
2. Displacement is the net change in position: final position minus initial position.
3. Since the car ends up back at its starting point (home), the net change in position is zero.
4. The text confirms this directly: "The total distance that your car travels is 10 km, but the total displacement is 0."
5. So distance = 10 km while displacement = 0 km -- distance and displacement are not interchangeable once the path doubles back.
_Source: OpenStax Physics Ch 2 "Motion in One Dimension", p.59 Fig. 2.6 §2.1 Relative Motion, Distance, and Displacement_
Related questions
A bus speeds up uniformly from 6 metres per second to 18 metres per second in 4 seconds. WWhat does the area under a velocity versus time graph give?A learner walks a long curved path from home to school. Which quantity depends only on theOn the jet car's velocity-time graph, a rectangular region (20 m/s over 30 s) contributes On a velocity-versus-time graph, what does the area under the curve represent?To find a jet car's instantaneous velocity at t = 25 s, the tangent line to its position-tOn a jet-powered car's position-time graph, two points are (0.50 s, 525 m) and (6.4 s, 200On a graph of position versus time, what physical quantity does the slope of the line repr